(v^2-2)(2v+5)=0

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Solution for (v^2-2)(2v+5)=0 equation: 


Simplifying
(v2 + -2)(2v + 5) = 0

Reorder the terms:
(-2 + v2)(2v + 5) = 0

Reorder the terms:
(-2 + v2)(5 + 2v) = 0

Multiply (-2 + v2) * (5 + 2v)
(-2(5 + 2v) + v2(5 + 2v)) = 0
((5 * -2 + 2v * -2) + v2(5 + 2v)) = 0
((-10 + -4v) + v2(5 + 2v)) = 0
(-10 + -4v + (5 * v2 + 2v * v2)) = 0
(-10 + -4v + (5v2 + 2v3)) = 0
(-10 + -4v + 5v2 + 2v3) = 0

Solving
-10 + -4v + 5v2 + 2v3 = 0

Solving for variable 'v'.

The solution to this equation could not be determined.

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